[英]Is there a modifier to change the label color of SwiftUI Picker?
I want to change the label color of SwiftUI Picker
from blue to black, tried .foregroundColor(.black)
and .tint(.black)
, but the color remains blue.我想将SwiftUI Picker
的 label 颜色从蓝色更改为黑色,尝试.foregroundColor(.black)
和.tint(.black)
,但颜色仍然是蓝色。
@State var privacy = Privacy.open
enum Privacy: String, CaseIterable, Identifiable {
case open = "Open"
case closed = "Closed"
var id: String {
self.rawValue
}
}
var body: some View {
Picker("privacy", selection: $privacy) {
ForEach(Privacy.allCases) { value in
Text(value.rawValue)
.tag(value)
}
}
.pickerStyle(.menu)
.tint(.black)
.foregroundColor(.black)
}
I tried foregroundStyle
and accentColor
and only accentColor
worked.我尝试了foregroundStyle
和accentColor
并且只有accentColor
有效。 It does have a future deprecation warning, but you should be able to use it for now.它确实有一个未来的弃用警告,但你现在应该可以使用它。
.accentColor(.orange)
As the other user has mentioned, .accentColor(.orange)
works, but has a depreciation warning.正如其他用户提到的, .accentColor(.orange)
有效,但有折旧警告。
Using .tint(.orange)
does not have this warning and will color the picker text.使用.tint(.orange)
没有此警告,并且将为选择器文本着色。
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