如果元素在数组中有一个空值。 然后告诉所有下一项为假

Question

Hellow All. I heve some issue. I want to find in an array the first element with an empty value and set all other elements to fals. I've tried many different options. But so far, only the variant with the current element works.

 someArray.map(e: any, inex: any, a: any) => {

  if (e.instruction.length > 0) {
    return e.isEmpty = false
  }

  return ( someHtml)
}

Answer 1

Try this code.

const isNotEmptyFirstItem = someArray[0].instruction.length > 0;
const updatedArray = isNotEmptyFirstItem && someArray.map(item => item.isEmpty = false);
}

And you can do what you want with the updatedArray.

Answer 2

const FuncToCheck = (el) => el === true
cosnt faindElemIndex = someArray.faindIndex((el) => FuncToCheck(el))
const setCheck = () => {
  if (indexOfMap > faindElemIndex) { return false } 
    else return true
}