如何在golang中直接打开加密的sqlite3 db文件

Question

open db code:

    dbname := `***.db`
    key := "dd85344"
    dbnameWithDSN := dbname + fmt.Sprintf("?_pragma_key=x'%s'&_pragma_cipher_page_size=4096", key)
    db, err := gorm.Open(sqlite.Open(dbnameWithDSN), &gorm.Config{})

or:

    dbname := `***.db`
    key := "dd85344"
    dbnameWithDSN := dbname + fmt.Sprintf("?_pragma_key=x'%s'&_pragma_cipher_page_size=4096", key)
    db, _ := sql.Open("sqlite3", dbname)

The password is definitely correct, but my key is 7 bits and the official word is that it must be 32 bytes hexadecimal code.

I think the problem is here, but I don't know how to convert it next...

Answer 1

    db, err := sql.Open("sqlite3", `xxx.db?_pragma_key=x'dd85344'&_pragma_cipher_page_size=1024`)
    if err != nil {
        t.Fatal(err)
    }
    rows, err := db.Query("SELECT id,value FROM userinfo")
    if err != nil {
        t.Fatal(err)
    }

return err: file is not a database