关于在JS中用正则表达式分割字符串的问题

Question

I am learning some regular Expressions.

Now am I trying to get the street and the house number out of a string.

So this is my string "Driesstraat(Ide) 20". Driesstraat is the street name. (Ide) is an acronym for the municipality. 20 is the house number.

let re =   /^(\d*[\p{L} \d'\/\\\-\.]+)[,\s]+(\d+)\s*([\p{L} \d\-\/'"\(\)]*)$/iu
    
let match = adresInput.value.match(re)
if (match){
 match.shift();
    
 console.log(match.join('|'));
} 

The above code works when their is no (Ide). I get this string out of a Belgian Eid reader.

thank you in advance

Answer 1

First things first, (...) is not matched with your (\d*[\p{L} \d'\/\\\-\.]+) pattern, so you need to add (?:\(\p{L}*\))? or (?:\([^()]*\))? right after that pattern to optionally match a part of a string between parentheses. (?:\(\p{L}*\))? will match only letters between round brackets and (?:\([^()]*\))? will match any chars other than ( and ) between round brackets.

Besides, when using regular expressions with /u flag you must make sure you only escape what must be escaped inside character classes. It means, you overescaped several chars inside [...] . You need not escape ( , ) , . and you can even avoid escaping - when if it is put at the end of the character class. The chars that must be escaped inside character classes in ECMAScript regex flavor are \ , ] , and ^ must be escaped if it is at the start of the character class. Although the - can also be escaped it is best practice to put it at the end of the character class unescaped.

So, you can use

/^(\d*[\p{L} \d'/\\.-]+)(?:\([^()]*\))?[,\s]+(\d+)\s*([\p{L} \d/'"()-]*)$/u

See the regex demo .

Note you do not even have to escape / inside character classes in ECMAScript regex flavor in JavaScript.

See a JavaScript test:

 let re = /^(\d*[\p{L} \d'/\\.\-]+)(?:\([^()]*\))?[,\s]+(\d+)\s*([\p{L} \d/'"()-]*)$/u; console.log(re.test("Driesstraat(Ide) 20"));