如何将特定键值从 object 转换为数组 javascript

Question

I would like to know how to get particular key from object and convert to array in javascript

var result = Object.entries(obj).includes(obj.name || obj.country || obj.account || obj.pincode).map(e=>e);

var obj = {
  "name" : "Sen",
  "country": "SG",
  "key" : "Finance",
  "city": "my",
  "account":"saving",
  "pincode":"1233"
}

Expected Output

["Sen", "SG", "saving", "1233"]

Answer 1

Create an array of requested keys , and then map it and take the values from the original object:

 const obj = {"name":"Sen","country":"SG","key":"Finance","city":"my","account":"saving","pincode":"1233"} const keys = ['name', 'country', 'account', 'pincode'] const result = keys.map(k => obj[k]) console.log(result) // ["Sen", "SG", "saving", "1233"]

Answer 2

I think you can try it like this.

There're other ways to get that result, too. Here's just a simple solution.

var obj = {
  "name" : "Sen",
  "country": "SG",
  "key" : "Finance",
  "city": "my",
  "account":"saving",
  "pincode":"1233"
}

let arrObj = []

let result = arrObj.push(obj.name, obj.country, obj.account, obj.pincode)

console.log(arrObj)

Answer 3

If you want an array based on a known, hardcoded list of properties, the easiest option is an array literal:

const result = [obj.name, obj.country, obj.account, obj.pincode];

A benefit of this approach is that it guarantees the order of values in the array. While the order is predictable in your example (one onject literal), f your obj s are created in different places, the order of the values may not always be the same.

Answer 4

    var obj = {
      "name" : "Sen",
      "country": "SG",
      "key" : "Finance",
      "city": "my",
      "account":"saving",
      "pincode":"1233"
    }
    const Names = Object.keys(obj);
    console.log(Names);
    const Values = Object.values(obj);
    console.log(Values);
const entries = Object.entries(obj);
console.log(entries);

Answer 5

filter by a Set containing just the keys you want, then use map to return just the values:

const keys = new Set(['name', 'country', 'account', 'pincode'])

Object.entries(obj).filter(entry => keys.has(entry[0])).map(entry => entry[1])