python csv 读取列 function 没有给出正确的 Z78E6221F6393D1356681DB398F14CED6

Question

I am trying to read a single column in my csv data file with the following function, however when I run the function it only prints out the header instead of the whole column.

I want the function to print out a single column from my csv file (including the heading) in the form of a list.

I am very confused about where I am going wrong and would be very appreciative for any help.

thank you in advance for your response.

def read_column(filename, column:int):
    file = open ('data1.csv', 'r')
    for rows in csv_file:
        column = (rows.split(',')[0])
        return column

Answer 1

Please enter the values in the list and return the list:

def read_column(filename, column:int):
    file = open ('data1.csv', 'r')
    list=[]
    for rows in csv_file:
        column = (rows.split(',')[0])
        list.append(column)
    return list

Answer 2

in your loop function you return only the first line you read.

So, if you want to get all the lines. Instead of return column at the first time you read it. You should store the value and return all the stored value at once.

def read_column(filename, column:int):
    file = open ('data1.csv', 'r')
    allLines = []
    for rows in csv_file:
        column = (rows.split(',')[0])
        allLines.append(column)
    
    # return all at once after read all lines.
    return allLines