对 CSV 文件中的每一行求和，并按特定值 bash 对其进行排序

Question

i have a question taking the below set Coma separated CSV i want to run a script in bash that sums all values from colums 7,8,9 from an especific city and show the row with the max value so Original dataset:

Row,name,city,age,height,weight,good rates,bad rates,medium rates
1,john,New York,25,186,98,10,5,11
2,mike,New York,21,175,87,19,6,21
3,Sandy,Boston,38,185,88,0,5,6
4,Sam,Chicago,34,167,76,7,0,2
5,Andy,Boston,31,177,85,19,0,1
6,Karl,New York,33,189,98,9,2,1
7,Steve,Chicago,45,176,88,10,3,0

the desire output will be

Row,name,city,age,height,weight,good rates,bad rates,medium rates,max rates by city
2,mike,New York,21,175,87,19,6,21,46
5,Andy,Boston,31,177,85,19,0,1,20
7,Steve,Chicago,45,176,88,10,3,0,13

im trying with this; but it gives me only the highest rate number so 46 but i need it by city and that shows all the row, any ideas how to continue?

awk 'BEGIN {FS=OFS=","}{sum = 0; for (i=7; i<=9;i++) sum += $i} NR ==1 || sum >max {max = sum}

Answer 1

You may use this awk:

awk '
BEGIN {FS=OFS=","}
NR==1 {
   print $0, "max rates by city"
   next
}
{
   s = $7+$8+$9
   if (s > max[$3]) {
      max[$3] = s
      rec[$3] = $0
   }
}
END {
   for (i in max)
      print rec[i], max[i]
}' file

Row,name,city,age,height,weight,good rates,bad rates,medium rates,max rates by city
7,Steve,Chicago,45,176,88,10,3,0,13
2,mike,New York,21,175,87,19,6,21,46
5,Andy,Boston,31,177,85,19,0,1,20

or to get tabular output:

awk 'BEGIN {FS=OFS=","} NR==1{print $0, "max rates by city"; next} {s=$7+$8+$9; if (s > max[$3]) {max[$3] = s; rec[$3] = $0}} END {for (i in max) print rec[i], max[i]}' file | column -s, -t

Row  name   city      age  height  weight  good rates  bad rates  medium rates  max rates by city
7    Steve  Chicago   45   176     88      10          3          0             13
2    mike   New York  21   175     87      19          6          21            46
5    Andy   Boston    31   177     85      19          0          1             20