将枚举分配为 object 类型的键的值

Question

Below is my Enum:

export enum MyEnum {
  Enum1 = 'Enum 1',
  Enum2 = 'Enum 2',
  Enum3 = 'Enum 3',
  Enum4 = 'Enum 4',
  Enum5 = 'Enum 5',
}

I want to create a type for the example object shown below:

const testData = {
  test1: {
    Enum1 = 'Enum 1',
    Enum2 = 'Enum 2',
  },
  test2: {
    Enum1 = 'Enum 1',
    Enum2 = 'Enum 2',
    Enum3 = 'Enum 3',
    Enum4 = 'Enum 4',
  },
  test2: {
    Enum1 = 'Enum 1',
    Enum2 = 'Enum 2',
    Enum4 = 'Enum 4',
  },
};

So far, I could come up with:

type FilteredBuyableMethods = {
  [key: string]: Partial<{
    [key in MyEnum]: string
  }>
};

How can I replace the string in [key in MyEnum]: string with the exact value of the key?

So if the key is Enum1 , the value for it should only be 'Enum 1' and so on. Thanks in anticipation.

Answer 1

Using the tricks from Use Enum as restricted key type in Typescript and Typescript: string literal union type from enum , you can construct a mapped type as follows:

type FilteredBuyableMethods = {
  [key: string]: Partial<{
    [key in keyof typeof MyEnum]: `${typeof MyEnum[key]}`
  }>
};

^{Notice the typeof MyEnum[key] parses as (typeof MyEnum)[key] .
( online playground )}

This will both prevent wrong keys (that are not keys of the enum), as well as wrong value (that don't fit to their key respectively).