有没有办法知道 function 是否在 promise 中被调用？

Question

Let's say I have this code, and I have written a function called handleSmell() in a package that others can use:

const streamSomeUrl = (url='https://salmon.net/river') => {

  console.info('...connecting...');
  const { data, headers } = await axios({
    url,
    method: 'GET',
    responseType: 'stream',
  });
  return new Promise((resolve, reject) => {
    data.on('data', (chunk) => {
       if(smellsFunny(chunk)) {
         // promise aware function
         handleSmell(chunk) // <--- behaves differently inside a promise. 
         // E.g. prints  "Smell inside a promise" 
       }
    });
  })
}

Is there a way, that the function handleSmell to tell if it's in a promise or not? By that I mean, it would behave differently to here:

readFile('/etc/fish', (err, data) => {
  if(smellsFunny(data)) {
     // promise aware function
     handleSmell(data) // <--- behaves differently inside a promise.
     // E.g. prints  "Smell *not* inside a promise" 
     ...
     }
});

I'm trying to figure out if I can do with without taking reject/resolve callbacks in to the handleSmell function (and then if missing, know I'm not in a promise).

As far as I'm aware I can't use the fact that different data is passed through, both chunk and data are strings/buffers?

Is this at all possible? I'm motivated by this question , mainly this bit from an answer:

Any time you are inside of a promise callback, you can use throw. However, if you're in any other asynchronous callback, you must use reject.

new Promise(function() {
  setTimeout(function() {
    throw 'or nah';
    // return Promise.reject('or nah'); also won't work
  }, 1000);
}).catch(function(e) {
  console.log(e); // doesn't happen
});

---

My preference is to throw, but I want to know if I call a reject callback (ie from the parent reject) it will work:

function handleSmell(suspectData, reject=False) {
  const inPromise = //?????
  if (inPromise && reject) {
    return reject('SMELLY REJECT!')
  } else if (inPromise) {
    throw new Error('SMELLY THROWN!')
  } else { console.error('SMELLY NON-PROMISE!') }
}
// Both these should work
new Promise(function() {
  setTimeout(function() {
    handleSmell('cheese');
}).catch(function(e) {
  console.log(e); // doesn't try to throw
});

new Promise(function(resolve, reject) {
  setTimeout(function() {
    handleSmell('cheese', reject);
  }, 1000);
}).catch(function(e) {
  console.log(e); // this works
});

The alternative is promisifying the non-promise (as per link).

But can I avoid that if possible?

Answer 1

Is this at all possible?

No, you cannot do that, and no, you shouldn't do that. What a function does should depend on its arguments, not on where it was called from.

I'm motivated by this question, mainly this bit from an answer:

Any time you are inside of a promise callback, you can use throw. However, if you're in any other asynchronous callback, you must use reject.

Well, handleSmell is not defined in a callback, it's a standalone synchronous function, so it should simply throw an exception.

The proper way to call such a function is either from within a try block, or from within a promise ( then ) callback.

new Promise((resolve, reject) => {
  setTimeout(() => {
    try {
      resolve(handleSmell('cheese'));
    } catch(err) {
      reject(err);
    }
  });
}).then(console.log, console.error);

new Promise((resolve, reject) => {
  setTimeout(() => {
    resolve('cheese');
  }, 1000);
}).then(handleSmell).then(console.log, console.error);
//      ^^^^^^^^^^^
// or .then(res => handleSmell(res)) for verbosity