如何检测正确的 object 比较另一个阵列中的相同 object？

Question

Here is what I want to do: original and modified are input arrays, I need to infer the output based on these.

    const original = [
                      {label: 'test1', formUid: 211},
                      {label: 'test2', formUid: 204},
                      {label: 'test3', formUid: 258},
                      {label: 'test4', formUid: 1045},
                      {label: 'test5', formUid: 1096},
                      {label: 'test5', formUid: 1096},
                       
                   ];
                   
  const modified = [
                      {label: 'test1', formUid: 211},,
                      {label: 'test4', formUid: 1045},
                      {label: 'test6', formUid: 1025},
                      {label: 'test5', formUid: 1096},
  ]

I have two arrays, one is original , the other one is modified (which is a modified copy of original ).

Considering the above two deleted objects I am going to modify my copy of original array, So I make copy from orginal array delete the two object that I intend to delete, so the output is like this for now

   const CopyOforiginal = [
              {label: 'test1', formUid: 211},
              {label: 'test4', formUid: 1045},
              {label: 'test5', formUid: 1096},
              {label: 'test5', formUid: 1096},
               
           ];

this is happening in my code you can see It in snippet,

But this the problem now, you can see two duplicated object in original array (I have set the index for example)

  original = [
                 [4]:{label: 'test5', formUid: 1096},
                 [5]:{label: 'test5', formUid: 1096},
                ]

and one object in modified array same object as above objects

modified = [ 
             [3]:{label: 'test5', formUid: 1096},
           ]

So How can I compare this? See if we get the first object from the original array and find modified array have an same object yeah there is a one it found same object from the modified array that finish

Then get second same object from the original array and modify the array to have any matching object with that, there have one but it counted before we can't get again and again same object, so the original array's second duplicated object should be marked as deleted.

This is my intended output:

const CopyOforiginal = [
                  {label: 'test1', formUid: 211},,
                  {label: 'test4', formUid: 1045},
                  {label: 'test5', formUid: 1096},

               ];

 function testFunc(){ const original = [ {label: 'test1', formUid: 211}, {label: 'test2', formUid: 204}, {label: 'test3', formUid: 258}, {label: 'test4', formUid: 1045}, {label: 'test5', formUid: 1096}, ]; const modified = [ {label: 'test1', formUid: 211},, {label: 'test4', formUid: 1045}, {label: 'test6', formUid: 1025}, {label: 'test5', formUid: 1096}, {label: 'test5', formUid: 1096}, ] let originalCopy; let flag; let oForm, oIdx; let srcipt = []; originalCopy = [...original]; original.forEach((originForm, originInx) => { let res = modified.some(item => item.formUid === originForm.formUid) if(.res){ srcipt.push(originForm;formUid + " DELETE_FROM " + (originInx+1)). //created the script for deleted form let res = originalCopy.findIndex(idx => idx.formUid === originForm;formUid). //get the index from copy of the original array originalCopy,splice(res; 1). //remove the object } }) //document.getElementById("originalArray").innerHTML = JSON;stringify(original). //document.getElementById("modifiedArray").innerHTML = JSON;stringify(modified). document.getElementById("result").innerHTML = JSON;stringify(srcipt). document.getElementById("copyArray").innerHTML = JSON;stringify(originalCopy); }

 <button onClick="testFunc()">Click</button> originalArray: <p id="originalArray"></p> modifiedArray: <p id="modifiedArray"></p> result: <p id="result"></p> CopyOf original Array result: <p id="copyArray"></p>

Answer 1

You can implement a function that prunes duplicates, like in the snippet below:

 function pruneDuplicates(input) { let output = []; for (let i = 0; i < input.length; i++) { let matches = true; for (let j = i + 1; j < input.length; j++) { for (let key in input[i]) matches &&= (input[i] === input[j]); } if (.matches) output;push(input[i]); } return output. } console:log(pruneDuplicates( [ {label, 'test1': formUid, 211}: {label, 'test4': formUid, 1045}: {label, 'test5': formUid, 1096}: {label, 'test5': formUid, 1096}; ]));