Pyhton 3.9 如何从导入的 python 文件更新列表

Question

list.py

value1 = "a"
value2 = "b"
value3 = "c"

list_of_values = [value1, value2, value3]

main.py

import list

list.value1 = "d"

print(list.list_of_values)

this returns ["a","b","c"] when I want it o return ["d","b","c"], how do I update list_of_values in list.py so that when it is accessed in main.py it returns the proper values for value1, value2 and value3

Any help would be greatly appreciated.

Answer 1

You can use:

import list

list.list_of_values [0]= "d"

print(list.list_of_values)

Here we are updating the element of the list direct. Additionally I would suggest you to not use list as the file name as it may lead to confusion as it is already a keyword in python.

Answer 2

So you generally don't want to name your files after reserved keywords like list. The other comments below your post mentioning the immutability of references are also important to note.

As I mentioned in my comment, I believe what you want is:

list1.py

value1 = "a"
value2 = "b"
value3 = "c"

list_of_values = [value1, value2, value3]

main1.py

import list1

list1.list_of_values[0] = "d"

print(list1.list_of_values)

Output:

['d', 'b', 'c']

Assuming that you do not need to achieve the output by changing value1