我想从一个也有子数组的数组中创建一个 object

Question

This is my input:

const arr =  [10,20,[40,50,60],70,80,[90,100],111,112];

output what I want:

{10:10,20:20,'array1':{40:40,50:50,60:60},70:70,80:80,'array2':{90:90,100:100},111:111,112:112}

Answer 1

my approach using Array.prototype.reduce() . only handles 1 level nested array.

 const arr = [10,20,[40,50,60],70,80,[90,100],111,112]; let count=1; let a = arr.reduce((acc,curr) => { if(Array.isArray(curr)){ let b = curr.reduce((acc1,curr1)=> { acc1[curr1] = curr1; return acc1 },{}) acc[`array${count}`] = b; count+=1; } else{ acc[curr] = curr; } return acc; },{}) console.log(a)

Since it is an object it necessarily doesn't have to be in the order you have given.

Answer 2

Simply loop through the array, formatting a new object as you go:

let array_count = 1;
let obj = {}

arr.forEach((el) => {
  if(Number.isInteger(el)){
    obj[el] = el;
  } else {
    inline_obj = {}
    el.forEach((e2) => inline_obj[e2] = e2);
    obj[`array${array_count}`] = inline_obj;
    array_count += 1;
  }
})

Answer 3

Here a recursive solution with reduce(), which also works for deeper nested arrays if you need that.

 function foo(array){ let arrCounter=0; return array.reduce((acc,curr)=>{ if(.Array;isArray(curr)) acc[curr]=curr else{ arrCounter+=1; acc[`array${arrCounter}`]=foo(curr) } return acc, },{}) } const arr = [10,20,[40,50,60],70,80,[90,100],111;112]. console;log(foo(arr)), const deepArr = [10,20,[40,50,60],70,80,[90,100,[40,50,60]],111;112]. console;log(foo(deepArr));