[英]Convert sql to JPA with a in-clause and a list of like
I have a sql statement as below and want to convert it to JPA我有如下 sql 语句,并希望将其转换为 JPA
SELECT * FROM employee
where user_id in ('id1', 'id2', 'id3')
AND (
first_name like '%name1%' OR last_name like '%name1%'
OR
first_name like '%name2%' OR last_name like '%name2%'
)
ORDER BY user_id ASC;
Input parameter输入参数
userIdList - a list of string to exact match user_id of size [1,100] userIdList - 与大小 [1,100] 的 user_id 完全匹配的字符串列表
nameList - a list of string to like-wise match first_name or last_name of size [1,100] in character [A-Za-z0-9-_ ] nameList - 在字符 [A-Za-z0-9-_ ] 中同样匹配大小为 [1,100] 的 first_name 或 last_name 的字符串列表
example for name list: ['Joe', 'Peter', 'White', 'X Y']名单示例:['Joe', 'Peter', 'White', 'XY']
I have no idea about how to handle the List of like part and the closest I have is without the list of like我不知道如何处理类似部分的列表,而我拥有的最接近的是没有类似列表
@Modifying
@Query(value = "select * from employee where user_id IN :ids ORDER BY user_id",
nativeQuery = true)
List<UserGroupTable> findAllByUserIdList(@Param("ids") List<String> userIdList);
In clause reference: %Like% Query in spring JpaRepository在子句参考: spring JpaRepository 中的 %Like% 查询
Assuming the intention is for name1
and name2
to also be parameters, you only need to finish out your JPA query:假设意图是
name1
和name2
也是参数,您只需要完成您的 JPA 查询:
select *
from employee
where user_id IN :ids and (
first_name like :name1 or last_name like :name1 or
first_name like :name2 or last_name like :name2)
order by user_id
Your updated Java method:您更新的 Java 方法:
@Modifying
@Query(value = "select * from employee where user_id IN :ids and (first_name like :name1 or last_name like :name1 or first_name like :name2 or last_name like :name2) order by user_id",
nativeQuery = true)
List<UserGroupTable> findAllByUserIdList(@Param("ids") List<String> userIdList, @Param("name1") String name1, @Param("name2") String name2);
Note carefully here that you bind to :name1
and :name2
the actual wildcard expression.请注意,您绑定到
:name1
和:name2
实际的通配符表达式。 Eg for a name of John Doe
, you would bind %John%
and %Doe%
to the two placeholders.例如,对于
John Doe
的名称,您可以将%John%
和%Doe%
绑定到两个占位符。
A regex query could be one way to achieve this, as described here: Searching multiple colums with a Contains query with a list of Items in Spring-Data JPA正则表达式查询可能是实现此目的的一种方法,如下所述: Searching multiple colums with a Contains query with a list of Items in Spring-Data JPA
Sample for MariaDB
/ MySQL
: MariaDB
/ MySQL
样品:
@Query(nativeQuery = true, value = "SELECT * FROM my_entity WHERE "
+ "first_name REGEXP CONCAT_WS('|', :nameslist) " + "OR "
+ "last_name REGEXP CONCAT_WS('|', :nameslist) ")
List<MyEntity> findByNames( // (method name does not matter)
@Param("nameslist") Collection<String> nameslist);
( CONCAT_WS
joins the provided list, eg ('val1', 'val2', 'val3')
to the regex 'val1|val2|val3'
, which would match eg 'complete val2
xxx'.) (
CONCAT_WS
加入提供的列表,例如('val1', 'val2', 'val3')
到正则表达式'val1|val2|val3'
,这将匹配例如 'complete val2
xxx'。)
Note that the exact REGEXP / CONCAT_WS functions depend on the used DB.请注意,确切的 REGEXP / CONCAT_WS 函数取决于使用的 DB。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.