在长字符串中的符号之间提取特定数字

Question

I have a long string captured from a log txt file which have sequence as below:

526136|20190403164654| 3 |06010003530075508541|1|8801851088890|

Is there any method to capture the 3rd field, which is the "3" value from each line using regex? I am aware that i can use the findall function to search for all number values and then capture the 3rd element in the list. Is there any other methods that is more efficient and simpler in coding? Thanks all

Answer 1

You don't need a regex for this, you can just .split() and find the Nth element!

>>> s = "526136|20190403164654|3|06010003530075508541|1|8801851088890|"
>>> s.split("|")[2]
'3'

Answer 2

import re
text = "526136|20190403164654|3|06010003530075508541|1|8801851088890"

pattern = r"\|\d\|"
new_text = re.search(pattern,text)
print(new_text)

#or

new_text = text.split("|")
print(new_text[2])

Answer 3

Try this:

>>> a = """1|2|3|4|5|
... 6|7|8|9|10|
... 11|12|13|14|15|
... 16|17|18|19|20|"""
>>> re.findall(r'^.*?\|.*?\|([\d]*?)\|', a, 10)
['3', '8', '13', '18']

Answer 4

import re ptrn = re.compile(r"\|") s = "526136|20190403164654|3|06010003530075508541|1|8801851088890|" number = re.split(ptrn, s)[2]