单击操作按钮后如何在不打开应用程序的情况下关闭通知？

Question

I am showing a notification using awesome_notifications and there is action buttons that dismiss the notification, but the problem is if the app is in the background, and the action button clicked, then it dismisses the notification but open the app too which I don't want. So how can I just dismiss the notification when the action button is clicked without opening the app? The notification also contains another action button that opens the app but the second should not. What should I do in that case?

This is what currently happens:

Code to show notification:

AwesomeNotifications().createNotification(
         content: NotificationContent(
           id: 333,
           title: 'Incoming Call',
           body: 'from $callerName',
           category: NotificationCategory.Call,
           channelKey: 'call_channel',
           largeIcon: 'asset://assets/images/logo_square.png',
           wakeUpScreen: true,
           fullScreenIntent: true,
           autoDismissible: false,
           showWhen: true,
           displayOnBackground: true,
           displayOnForeground: true,
           payload: {
             "callerName": callerName,
             "callerUsername": callerUsername,
             "callerID": callerID,
             "callerToken": callerToken,
             "callerImage": callerImage,
           },
         ),
         actionButtons: [
           NotificationActionButton(
               key: 'ACCEPT',
               label: 'Accept Call',
               color: Colors.green,
               autoDismissible: true,
           ),
           NotificationActionButton(
               key: 'REJECT',
               label: 'Reject Call',
               isDangerousOption: true,
               autoDismissible: true,
           ),
         ]
     );

Answer 1

Found the answer while surfing the GitHub Repository of awesome_notifications . The notification can straightly be dismissed without opening the app by adding buttonType as ActionButtonType.DisabledAction in the NotificationActionButton

just like this:

NotificationActionButton(
   key: 'DISMISS',
   label: 'Dismiss',
   autoDismissible: true,
   buttonType: ActionButtonType.DisabledAction,
   isDangerousOption: true
)

Note: Doing so will not trigger any receivedAction in the actionStream .