[英]better way to replace string with various scenarios in javascript
How to replace special characters for different pattern of same string in javascript如何替换 javascript 中相同字符串的不同模式的特殊字符
am passing one string at a time and below are string patterns我一次传递一个字符串,下面是字符串模式
var str1="2456 #02-567"
var result = str1.replace(/#/g, '')
var str1="2-567 2456"
var result = str1.replace(/^/g, '0')
for these strings
2456 #02-567 , 2456 02-567, 2456 2-567,2456 #2-567
Expected Output
2456 02-567
===========
for these strings
#02-567 2456 , 2-567 2456, 02-567 2456, #2-567 2456
Expected Output
02-567 2456
May be there is a clever solution, but this should work:可能有一个聪明的解决方案,但这应该有效:
let str = ["2456 #02-567", "2456 02-567", "2456 2-567","2456 #2-567","#02-567 2456", "2-567 2456", "02-567 2456", "#2-567 2456","1234 12-345","1234 #12-345","#12-345 1234"]; //1234 12-345" or "1234 #12-345" or "#12-345 1234" for(let st of str) console.log(st.replace(/#?(\d)?(\d-)/g,replacer)) function replacer(match, p1, p2, offset, string){ let replaceSubString = p1 || "0"; replaceSubString += p2; return replaceSubString; }
I'm using a captouring group (expression in the parenthesis in the regular expression) that can be referenced in the second parameter of replace
function with $1
(1 because is the first captouring group).我正在使用一个捕获组(正则表达式括号中的表达式),它可以在将 function replace
为$1
的第二个参数中引用(1 因为是第一个捕获组)。 The ?
?
instead point that the character is optional.而是指出该字符是可选的。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.