PHP preg_match html 中的多个标签

Question

I need to section off my html by multiple tags. from the start of the <h1> tag up to but not including the following <h1> tag. So far the expression I have works but only retrieves the first section. looking specifically for a preg_match solution. Would ideally like the solution to be dynamic (not matter the contents between the h1 tags or how many sections there are). Let me know (kinda new to regex in general). I know this may be a tricky question as I am new to php in general.

html

<h1>heading1</h1>
<img>
<p>para1</p>
<p>para2</p>
<h1>heading2</h1>
<img>
<p>para1</p>
<p>para2</p>
<h1>heading3</h1>
<img>
<p>para1</p>
<p>para2</p>

desired output or something similar:

array{
  [0]=> <h1>heading1</h1>
        <img>
        <p>para1</p>
        <p>para2</p>

  [1]=> <h1>heading2</h1>
        <img>
        <p>para1</p>
        <p>para2</p>

  [2]=> <h1>heading3</h1>
        <img>
        <p>para1</p>
        <p>para2</p>
}

my current expression is:

$regex = '#<\/p>\s*(<h2>.*?)<h2>#s';
$preg = preg_match_all($regex, $content, $matches);
print_r ($matches);

Very thankful for any help!

Answer 1

preg_match_all() won't return overlapping matches. Since your regexp ends with <h2> , which is the start of the next match, it won't return that next match.

Put the start of the next match into a lookahead so it's not included in the match.

$regex = '#<\/p>\s*(<h1>.*?)(?=<h1>)#s';