如何创建一个 function 省略 object 中的键/值对，并创建一个具有剩余属性和值的新 object？

Question

I've been working on creating an omit function with a source and keys parameter, that checks for keys within the source, and if they are found, those properties are omitted from the source, then create a new object literal with the remaining key/value pairs within the source. So far, I've been unsuccessful, and only have been able to create a function that does the opposite of creating an object with the keys found within the source. Can anyone help figure out what I'm missing? It would be very appreciated!

function omit(source, keys) {
  var includedSource = {};
  for (var key in source) {
    for (var i = 0; i < keys.length; i++) {
      if (keys[i] !== key) {
        includedSource[key] = source[key];
        console.log('source[keys[i]]:', source[keys[i]]);
        console.log('includedSource:', includedSource);
      }
    }
  }
  return includedSource;
}

  function omit(source, keys) {
    var includedSource = {};
    for (var key in source) {
      for (var i = 0; i < keys.length; i++) {
        if (keys[i] === key) {
          includedSource[key] = source[key];
          console.log('source[keys[i]]:', source[keys[i]]);
          console.log('includedSource:', includedSource);
          }
        }
     }
     return includedSource;
   }

Answer 1

Here is a simple implementation with flat object. Im not sure how would keys be declared if your object might be nested, and you would expect to extract some of N level of nested value/keys

const obj = {
  A: 1,
  B: 2,
  C: 3,
  D: 4
};

function omit(data, keys) {
  let result = {};

  for (let key in data) {
    if (keys.includes(key)) continue;

    result[key] = data[key];
  }

  return result;
}

console.log(omit(obj, ["A", "D"])) // {B: 2, C: 3}

Answer 2

You could destructure and rest for a new object.

 function omit(object, keys) { let _; // prevent to be global for (const key of keys) ({ [key]: _, ...object } = object); return object; } console.log(omit({ a: 1, b: 2, c: 3, d: 4 }, ['b', 'c']));

Answer 3

One approach is use Object.entries() and filter the entries out that have the unwanted keys then use Object.fromEntries() to create the new object from the filtered entries

 const omit = (data, keys) => { return Object.fromEntries( Object.entries(data).filter(([k]) =>.keys.includes(k)) ) } console:log(omit({ a,1:b,2:c,3:d,4}, ['a', 'b']))

Answer 4

Converting to entries with Object.entries and Object.fromEntries and then filtering said entries with <Array>.filter might work nicely:

const omit = (obj, keys) => Object.fromEntries(Object.entries(obj).filter(a=>!keys.includes(a[0])));

Answer 5

The problem with your solution is that, keys[i + 1] could be equal to key , even though keys[i] does not.

To correct your code, apply following change.

function omit(source, keys) {
  var includedSource = {};
  for (var key in source) {
    if(!keys.includes(key)) { // <--- Change this
       includedSource[key] = source[key];
       console.log('source[keys[i]]:', source[keys[i]]);
       console.log('includedSource:', includedSource);
    }
  }
  return includedSource;
}

Another approach, just for fun.

function omit(source, keys) {
    return Object.keys(source).reduce((acc, curr) => {
        return {...acc, ...(keys.includes(curr) ? {} : {[curr]: source[curr]})}
    }, {})
}