[英]Select Rows postgres SQL where Key = String for all elements of Jsonb Array
So I have a Postgres SQL table that has a column of the type jsonb array.所以我有一个 Postgres SQL 表,其中有一列类型为 jsonb 数组。 Looks like this more or less:
或多或少看起来像这样:
[{"adi": "cat", "status": "ACTIVE"}, {"adi": "dog", "status": "ACTIVE"}, {"adi": "bird", "status": "INACTIVE"}]
[{"adi": "fish", "status": "ACTIVE"}, {"adi": "dog", "status": "ACTIVE"}, {"adi": "reptile", "status": "ACTIVE"}]
So I want to select rows that only have animals with status ACTIVE in column 2.所以我想 select 行只有第 2 列中状态为 ACTIVE 的动物。
Any ideas of how to go about it?关于如何 go 的任何想法?
Thank you!谢谢!
Assuming the only two values are ACTIVE
and INACTIVE
you can use a SQL JSON/Path expression:假设只有两个值是
ACTIVE
和INACTIVE
,您可以使用 SQL JSON/Path 表达式:
select *
from the_table
where not the_column @@ '$[*].status == "INACTIVE"'
Another option is the contains operator @>
另一个选项是包含运算符
@>
select *
from the_table
where not the_column @> '[{"status": "INACTIVE"}]'
This returns all rows that do not contain a status with INACTIVE这将返回所有不包含状态为 INACTIVE 的行
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