[英]How to conditionally assign a struct to a variable?
The code is pretty self explanatory.该代码非常不言自明。 I am trying to have the dictionary variable be one of 3 structs.
我试图让字典变量成为 3 个结构之一。 There is likely a simple solution that escapes me at the moment.
目前可能有一个简单的解决方案让我无法理解。
func whichDictionaryToUse(flaps: Int, wind: Int) {
var dictionary = ()
var possibleWindDictionaries = Set<[Double:Double]>()
switch flaps {
case 10: dictionary = CorrectLD10Dict()
case 15: dictionary = CorrectLD15Dict()
case 35: dictionary = CorrectLD35Dict()
default: print("Present alert saying flaps value out of range")
}
switch wind {
case 10: possibleWindDictionaries = [dictionary.plusTenMinusTwoDic, dictionary.plusTenMinusOneDic, dictionary.plusTenZeroDic, dictionary.plusTenPlusOneDic, dictionary.plusTenPlusTwoDic]
…
struct CorrectLD10Dict: CorrectLDict {}
struct CorrectLD15Dict: CorrectLDict {}
struct CorrectLD35Dict: CorrectLDict {}
protocol CorrectLDict {}
func whichDictionaryToUse(flaps: Int, wind: Int) {
let dictionary: CorrectLDict
var possibleWindDictionaries = Set<[Double:Double]>()
switch flaps {
case 10: dictionary = CorrectLD10Dict()
case 15: dictionary = CorrectLD15Dict()
case 35: dictionary = CorrectLD35Dict()
default: print("Present alert saying flaps value out of range")
}
switch wind {
case 10: possibleWindDictionaries = [dictionary.plusTenMinusTwoDic, dictionary.plusTenMinusOneDic, dictionary.plusTenZeroDic, dictionary.plusTenPlusOneDic, dictionary.plusTenPlusTwoDic]
…
}
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