[英]How to create a wrapper for `std::make_unique<T>`?
I'd like to create a wrapper for std::unique_ptr<T>
and std::make_unique<T>
because I think they look ugly and take too long to type.我想为
std::unique_ptr<T>
和std::make_unique<T>
创建一个包装器,因为我认为它们看起来很难看并且需要很长时间才能输入。 (Yes, I'm that kind of person). (是的,我就是这样的人)。
I have completed my UniquePtr
type alias with no problem but cannot get my MakeUnique
to work.我已经毫无问题地完成了我的
UniquePtr
类型别名,但无法让我的MakeUnique
工作。 It seems to be a bit of a rabbit hole, and was wondering if anyone here might be able to give me a hand with this?这似乎有点像兔子洞,想知道这里是否有人可以帮我解决这个问题?
What I have so far:到目前为止我所拥有的:
template <class T>
using UniquePtr = std::unique_ptr<T>;
template<typename T, typename... Args>
UniquePtr<T> MakeUnique<T>(Args... args) // recursive variadic function
{
return std::make_unique<T>(args);
}
Many thanks in advance!提前谢谢了!
You need to forward properly the values, and you need to expand the pack.您需要正确转发值,并且需要扩展包。
First, make it compile:首先,让它编译:
template<typename T, typename... Args>
UniquePtr<T> MakeUnique(Args... args) // not recursive
{ // ^---- no need for <T> when defining function template
return std::make_unique<T>(args...); // the ... expands the pack
}
Then, you need to forward, because args...
will copy everything.然后,您需要转发,因为
args...
会复制所有内容。 You want to move rvalues, and copy lvalues:您想移动右值并复制左值:
template<typename T, typename... Args>
UniquePtr<T> MakeUnique(Args&&... args)
{
return std::make_unique<T>(std::forward<Args>(args)...);
}
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