获取 python 枚举 class 的名称

Question

Let's say that I have a class like this

class ErrorCreatingObjectResult(enum.Enum):
    NONE = 0
    OBJECT_ALREADY_EXIST = 1
    UID_NOT_REGESTIRE = 2
    CREATOR_NOT_REGESTIRE = 3

and an object with an attribute from this class

class CreatingObjectMessage:
    def __init__(self) -> None:
        self.message = 'done creating object'
        self.error = False
        self.errorType = ErrorCreatingObjectResult.NONE

and I want to generate the dict object from this class by calling

def convert2serialize(obj):
    if isinstance(obj, dict):
        return {k: convert2serialize(v) for k, v in obj.items()}
    elif hasattr(obj, "_ast"):
        return convert2serialize(obj._ast())
    elif not isinstance(obj, str) and hasattr(obj, "__iter__"):
        return [convert2serialize(v) for v in obj]
    elif hasattr(obj, "__dict__"):
        return {
            k: convert2serialize(v)
            for k, v in obj.__dict__.items()
            if not callable(v) and not k.startswith('_')
        }
    else:
        return obj

r = CreatingObjectMessage()
convert2serialize(r)

this giving me an empty results

Answer 1

Editing the convert2serialize function fixed it

def convert2serialize(obj):
    if isinstance(obj, enum.Enum):
        return {type(obj).mro()[0].__name__: obj.name}
    if isinstance(obj, dict):
        return {k: convert2serialize(v) for k, v in obj.items()}
    elif hasattr(obj, "_ast"):
        return convert2serialize(obj._ast())
    elif not isinstance(obj, str) and hasattr(obj, "__iter__"):
        return [convert2serialize(v) for v in obj]
    elif hasattr(obj, "__dict__"):
        return {
            k: convert2serialize(v)
            for k, v in obj.__dict__.items()
            if not callable(v) and not k.startswith('_')
        }
    else:
        return obj

Answer 2

Getting the name of an enum member's class is as easy as:

member.__class__.__name__