按 python3.x 升序对给定的二维数组进行排序

Question

I am a python beginner, please help me with this python case.

Sort given 2d array in order of ascending.Flatten the 2D array, and sort it such that first sort order is the first number, second sort order is the second number'''# Example:input_arr = [ ['55-29', '55-32', '62-3', '84-38'], ['36-84', '23-53', '22-58', '48-15'], ['72-80', '48-6', '11-86', '73-23'], ['93-51', '55-11', '93-49', '72-10'], ['93-66', '71-32', '16-75', '55-9'],] ouput_arr = ['11-86', '16-75', '22-58', '23-53', '36-84', '48-6', '48-15', '55-9', '55-11', '55-29', '55-32', '62-3', '71-32', '72-10', '72-80', '73-23', '84-38', '93-49', '93-51', '93-66'] def sort_2d_array(input_arr=input_arr) -> list: #TODO pass

Answer 1

Try this you need to flatten your list into single list like this

tmp = [t for x in input_arr for t in x]

then do the sorting based on first element before the - , like this

print(list(sorted(tmp,key=lambda x: int(x.split('-')[0]))))

this will give you your desired output.

['11-86', '16-75', '22-58', '23-53', '36-84', '48-15', '48-6', '55-29', '55-32', '55-11', '55-9', '62-3', '71-32', '72-80', '72-10', '73-23', '84-38', '93-51', '93-49', '93-66']

for second condition you can try

print(list(sorted(tmp,key=lambda x: (int(x.split('-')[0]) , int(x.split('-')[1])))))

this will give you

['11-86', '16-75', '22-58', '23-53', '36-84', '48-6', '48-15', '55-9', '55-11', '55-29', '55-32', '62-3', '71-32', '72-10', '72-80', '73-23', '84-38', '93-49', '93-51', '93-66']