我的 if/else/elif 语句不起作用或我不知道如何使用它

Question

I wanted to make a menu for a restaurant. Because I am new, I wanted to make not a-lot of choices so I got a random excuse but thats not my problem right now. I just need help as when I do my if/else/elif statement, well either idk how to use it or i just have a mistake in my code pls help... so this is what i have so far:

import sys

def _menu_():
    print('|--------------------------------|')
    print('|Kids menu:                      |')
    print('| Chicken nuggets(G)           3$|')
    print('| Medium size MAC(G)           5$|')
    print('| EXTRA Fries (GF)         +1.50$|')
    print('|*all menu comes with fries*     |')
    print('|G = GLUTEN   GF = GLUTENFREE    |')
    print('|--------------------------------|')

def _menu_COTD():
    print('|--------------------------------|')
    print('|CATCH OF THE DAY:               |')
    print('| Beef tenderloin (grilled)   24$|')
    print('| Grilled salmon,tuna/mayo 12$   |')
    print('| G = GLUTEN   GF = GLUTENFREE   |')
    print('|--------------------------------|')

def _menu_BOTH():
    print('|--------------------------------|')
    print('|Kids menu:                      |')
    print('| Chicken nuggets(G)           3$|')
    print('| Medium size MAC(G)           5$|')
    print('| EXTRA Fries (GF)         +1.50$|')
    print('|*all menu comes with fries*     |')
    print('|G = GLUTEN   GF = GLUTENFREE    |')
    print('|--------------------------------|')
    print('                                  ')
    print('                                  ')
    print('|--------------------------------|')
    print('|CATCH OF THE DAY:               |')
    print('| Beef tenderloin (grilled)   24$|')
    print('| Grilled salmon,tuna/mayo    12$|')
    print('| G = GLUTEN   GF = GLUTENFREE   |')
    print('|--------------------------------|')
    
    



    
print('Owner:')
print ('hello, i am the owner of the restaurant, unfortunately we have been robbed and all our food is gone except for our catch of the day and our kids menu')
print('    ')
print('is it ok or you want to go to another restaurant (knowing that our prices reduced by 75%)')
print('write "yes" if you want to eat here and write "no" to go somewhere else')

menu_choice = input('will you stay?')
if menu_choice == 'yes':
    print('ok great so what will you take?')

    
else:
    print('ok then, enjoy you expensive other restaurant')
    sys.exit()

menu_choice_2 = input('Kids menu, Catch of the day, or both?')

if menu_choice_2 == 'kids menu':
    _menu_
    
if: menu_choice_2 == 'Catch of th day':
    _menu_COTD
    
if: menu_choice_2 == 'Both':
    _menu_BOTH

so when it says menu_choice_2 i basically want to have either _menu_ (the kids menu) _menu_COTD (the catch of the day) and _menu_BOTH (which is both, _menu_ and _menu_COTD . pls help.. i dont know how to fix this... thanks.

• Hanter_yt

Answer 1

There are two errors.

• First, there are unnecessary colon(:) for the last two if statement.

• Second, you need a parenthesis to call the function (eg, menu ())

I just fixed the last part of the code, so that you can call the functions:

if menu_choice_2 == 'kids menu':
    _menu_()

if menu_choice_2 == 'Catch of th day':
    _menu_COTD()

if menu_choice_2 == 'Both':
    _menu_BOTH()

Answer 2

You're gonna have to call your function. Right now when you write menu , it evaluates to nothing. Instead, write _menu_() and same for other functions too. Also you have a typo in your last if statements, remove the colons from in front of if statements