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在 pandas dataframe MultiIndex 中用 None 替换 nan

[英]Replacing nan with None in pandas dataframe MultiIndex

I am trying to replace nan with None in a pandas dataframe MultiIndex.我试图在 pandas dataframe MultiIndex 中用 None 替换 nan。 It seems like None is converted to nan in MultiIndex (but not in other index types).似乎 None 在 MultiIndex 中被转换为 nan (但不是在其他索引类型中)。

Following does not work (Taken from the question Replace NaN in DataFrame index )以下不起作用(取自问题Replace NaN in DataFrame index

df = pd.DataFrame([['a', True, 1], ['b', True, 2], ['c', False, 3], ['d', None, 4]], columns=['c1', 'c2', 'c3'])
df.set_index(['c1','c2'], inplace=True)
df.index = pd.MultiIndex.from_frame(df.index.to_frame().fillna(np.nan).replace([np.nan], [None]))
df
          c3
c1 c2       
a  True    1
b  True    2
c  False   3
d  NaN     4
type(df.index[3][1])
<class 'float'>

Neither does也没有

index_tuples = [tuple(row) for row in df.index.to_frame().fillna(np.nan).replace([np.nan], [None]).values]
pd.MultiIndex.from_tuples(index_tuples)
MultiIndex([('a',  True),
            ('b',  True),
            ('c', False),
            ('d',   nan)],
           )

type(df.index[3][1])
<class 'float'>

It seems None is converted to NaN in MultiIndex.似乎在 MultiIndex 中 None 被转换为 NaN。

PS. PS。 It works for other index types:它适用于其他索引类型:

df = pd.DataFrame([['a', True, 1], ['b', True, 2], ['c', False, 3], ['d', None, 4]], columns=['c1', 'c2', 'c3'])
df.set_index('c2', inplace=True)
>>> df
      c1  c3
c2          
True   a   1
True   b   2
False  c   3
NaN    d   4
>>> df.index = df.index.fillna(value=np.nan).to_series().replace([np.nan], [None])
>>> df
      c1  c3
c2          
True   a   1
True   b   2
False  c   3
NaN    d   4
>>> type(df.index[3])
<class 'NoneType'>
>>> 

The only way I managed to do it is by manipulating the numpy array directly.我设法做到这一点的唯一方法是直接操作 numpy 阵列。 Seems like any assignment of None values by a MultiIndex in pandas results in conversion to NaN似乎MultiIndex中的 MultiIndex 对None值的任何分配都会导致转换为NaN

import pandas as pd
import numpy as np
df = pd.DataFrame([['a', True, 1], ['b', True, 2], ['c', False, 3], ['d', None, 4]], columns=['c1', 'c2', 'c3'])
df.set_index(['c1','c2'], inplace=True)

def replace_nan(x):
    new_x = []
    for v in x:
      try:
        if np.isnan(v):
          new_x.append(None)
        else:
          new_x.append(v)
      except TypeError:
        new_x.append(v)
    return tuple(new_x)


print('Before:\n', df.index)
idx = df.index.values
idx[:] = np.vectorize(replace_nan, otypes=['object'])(idx) # Replace values in np.array
print('After:\n', df.index)

Result:结果:

Before:
 MultiIndex([('a',  True),
            ('b',  True),
            ('c', False),
            ('d',   nan)],
           names=['c1', 'c2'])
After:
 MultiIndex([('a',  True),
            ('b',  True),
            ('c', False),
            ('d',  None)],
           names=['c1', 'c2'])

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