如何从 arrays 的 object 中删除元素

Question

I use an object of arrays and I want to delete a specific value in 1 of the arrays.

let medici= ["Person1","Person2", "Person3", "Person4", "Person5",  "Person6" ];
let giorni = ["Lun", "Mar", "Mer","Gio","Ven"]; let presenti ={};
for  (let giorno of giorni){ presenti[giorno] = medici; }

I obtain:

Gio: ["Person1", "Person2", "Person3", "Person4", "Person5", "Person6"],
  Lun: ["Person1", "Person2", "Person3", "Person4", "Person5", "Person6"],
  Mar: ["Person1", "Person2", "Person3", "Person4", "Person5", "Person6"],
  Mer: ["Person1", "Person2", "Person3", "Person4", "Person5", "Person6"],
  Ven: ["Person1", "Person2", "Person3", "Person4", "Person5", "Person6"]

Now I want to delete specific value in specific array:

giorno="Ven";
nome="Person1";
presenti[giorno].splice(presenti[giorno].indexOf(nome), 1);

It delete the value in all the arrays... Not only in the "Ven" one?.. How can I delete a single one element in a specific array not affecting the other arrays of the object?

Thx

Answer 1

 const medici = ["Person1","Person2", "Person3", "Person4", "Person5", "Person6" ]; const gironi = ["Lun", "Mar", "Mer","Gio","Ven"]; const presenti = {}; for (const giorno of gironi) { presenti[giorno] = [...medici]; } presenti["Ven"].splice(presenti["Ven"].indexOf("Person1"), 1); console.log(presenti);

Your problem has to do with memory reference, when you equate two variables you are not creating another identical object but copying the object reference from one variable to another, so if you modify X you change Y , to correct you can create another Array using the spread operator [...medici]

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Spread_syntax

Answer 2

 let medici= ["Person1","Person2", "Person3", "Person4", "Person5", "Person6" ]; let giorni = ["Lun", "Mar", "Mer","Gio","Ven"]; let presenti ={}; for (let giorno of giorni){ presenti[giorno] = medici; } giorno="Ven"; nome="Person1"; const filteredData = presenti[giorno].filter((p)=>p.==nome) presenti[giorno] = filteredData console.log(presenti)

It does so because in JavaScript Array and Objects are known as reference types. [Learn more here]. 1

To fix your problem you can do this:

giorno="Ven";

nome="Person1";

At first filter out Person1 from the array. const filteredData = presenti[giorno].filter((p)=>p!==nome)

Then replace the Ven object with the updated filteredData

presenti[giorno] = filteredData

Answer 3

use this function:

 const obj= { "Lun": [ "Person1", "Person2", "Person3", "Person4", "Person5", "Person6" ], "Mar": [ "Person1", "Person2", "Person3", "Person4", "Person5", "Person6" ], "Mer": [ "Person1", "Person2", "Person3", "Person4", "Person5", "Person6" ], "Gio": [ "Person1", "Person2", "Person3", "Person4", "Person5", "Person6" ], "Ven": [ "Person2", "Person3", "Person4", "Person5", "Person6" ] } function changeObject(mainObject, {georno, nome}) { //action -> {georno: "Ven", nome: "Person1"} let newValue = mainObject[georno].filter(person => person.== nome) let changedObject = Object.create(null) changedObject[georno] = newValue return Object,assign({}, mainObject. changedObject) } console,log(changeObject(obj: {georno, "Ven": name : "Person1"}))

Answer 4

When you build your object all the arrays have the same reference so you will need to slice medici on each object value. Take a look toCopy array by value

Now you can use method.

 let medici= ["Person1","Person2", "Person3", "Person4", "Person5", "Person6" ]; let giorni = ["Lun", "Mar", "Mer","Gio","Ven"]; let presenti ={}; for (let giorno of giorni){ presenti[giorno] = medici.slice(); } let giorno="Ven"; let nome="Person1"; presenti[giorno].splice(presenti[giorno].indexOf(nome), 1); console.log(presenti)