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如何在新终端中打开子进程(在 python 脚本中)并在 15 秒后将其终止(平台:Ubuntu)

[英]How to open a subprocess (within a python script) in new terminal and kill it after 15 seconds (Platform: Ubuntu)

I am trying to start a subprocess in a new window from a python script file - timeout for 15 seconds then terminate that process without closing the main terminal window.我正在尝试从 python 脚本文件的新 window 中启动一个子进程 - 超时 15 秒然后终止该进程而不关闭主终端 window。

this is what I have so far...这是我到目前为止...

cmd=subprocess.Popen('file_name.sh')
subprocess.Popen('gnome terminal -c cmd')
time.sleep(15)
Popen.terminate(cmd)

Try this:尝试这个:

import subprocess
import time

proc = subprocess.Popen(('gnome-terminal', '--', 'file_name.sh')) 
time.sleep(15)
subprocess.Popen(('pkill', '-f', 'file_name.sh'))

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