所以，我做了这个简单的 C 程序来给出 output，所以它对于正和零是正确的 integer 值是错误的

Question

How to get out of this first if else construct because when I input Negative values,because the condition here is checked and then it goes to the last else statement where this just prints zero

 #include<stdio.h>
      int main() {
         int x;
      scanf("%d", &x);

 if(x>0)
{

    printf("Positive");
    {
        if(x%2==0)
        {

            printf("Even");

        }
        else
        {

            printf("Odd");
        }

    }

I want this to be executed when I input negative values,but I'm unable to do so

    if(x<0)
    {
            
 printf("Negative");

        {

            if(x%2==0) {

                printf("Even");

            }
            else {

                printf("Odd");

            }


        }


    }

}

else {

    printf("Zero");

}
return 0;
}

Answer 1

Just reindent your code you will find strange { like the one after printf("Positive");

Juste removing this strange { and fixing your coding style will be:

#include<stdio.h>
int main() {
    int x;
    scanf("%d", &x);

    if ( x > 0 ) {
        printf("Positive");
        if ( x % 2 == 0 ) {
            printf("Even");
            
        } else {
            printf("Odd");
        }
    } else if( x < 0 ) {
        printf("Negative");
        if( x % 2 == 0 ) {
            printf("Even");
        } else {
            printf("Odd");
        }
    }   
    else {
        printf("Zero");
    }   
    return 0;
} 

easier to read, easier to debug

Answer 2

It seems the problem is an incorrect nesting of compound statements.

I can suggest the following solution.

#include <stdio.h>

int main( void )
{
    enum { Negative = -1, Zero = 0, Positive = 1};

    printf( "Enter a number: " );
    
    int x = 0;
    scanf( "%d", &x );

    int sign = ( 0 < x ) - ( x < 0 );

    switch (sign)
    {
    case Negative:
        printf( "Negative " );
        break;
    case Zero:
        puts( "Zero" );
        break;
    case Positive:
        printf( "Positive " );
        break;
    }

    if (sign != 0)
    {
        puts( x % 2 == 0 ? "even." : "odd." );
    }
}

The program output might look like

Enter a number: 10
Positive even.