在递归 function 中使用来自 main 的数组

Question

As part of a problem, I need to create a recursive function on a string.
Part of it is based on the nth element of Fibonacci.
The thing is that I need to get n ( the number of elements ) as an input, and only then I can create the array.
But I also need to create a recursive function that has to use the array.
I thought of adding the array to the function as a parameter but I'm not sure if that would decrease the function's efficiency.
So in case it would: Is there any way I can use that specific array in a function in c++? I calculate the array like this:

#include <bits/stdc++.h>
using namespace std;



char IOI(int n,int k) {
    if (n<3) {
        return n;
    }
    if (k<=fibo[n-2]) {
        return IOI(n-2,k);
    }
    else {
        return IOI(n-1,k-fibo[n-2]);
    }

}

int main() {
    int n,k;
    cin >> n >> k;

    int fibo[n+1];
    fibo[0] = 0;
    fibo[1] = 1;
    for (int i = 2; i<n; i++) {
        fibo[i] = fibo[i-1]+fibo[i-2];
    }

    cout << IOI(n,k)

Answer 1

Is there any way I can use that specific array in a function in c++?

Yes. Pass the array as an argument, using some form of indirection. Typically, this would be done using a parameter of type span .

---

 cin >> n >> k; int fibo[n+1];

This isn't allowed. The size of an array variable must be compile time constant in C++.

Answer 2

cin >> n >> k;
int * fibo = new int[n+1];

You can create array dynamically;

char IOI(int * fibo, int n,int k) {
...
}

And you can add the array as the function parameter.