在列表中搜索特定字符串

Question

How to search for every string in a list that starts with a specific string like:如何在列表中搜索以特定字符串开头的每个字符串，例如：

path = (r"C:\Users\Example\Desktop")
desktop = os.listdir(path)
print(desktop)
#['faf.docx', 'faf.txt', 'faad.txt', 'gas.docx']

So my question is: how do i filter from every file that starts with "fa"?所以我的问题是：我如何过滤每个以“fa”开头的文件？

Answer 1

For this specific cases, involving filenames in one directory, you can use globbing:对于这种特定情况，涉及一个目录中的文件名，您可以使用通配符：

import glob
import os

path = (r"C:\Users\Example\Desktop")
pattern = os.path.join(path, 'fa*')
files = glob.glob(pattern)

Answer 2

This code filters all items out that start with "fa" and stores them in a separate list此代码过滤掉所有以“fa”开头的项目并将它们存储在单独的列表中

filtered = [item for item in path if item.startswith("fa")]

Answer 3

All strings have a .startswith() method!所有字符串都有一个.startswith()方法！

results = []
for value in os.listdir(path):
    if value.startswith("fa"):
        results.append(value)