[英]How to show image in the table having the knowing the name of this
How can I show the image in the table knowing its name?如何在知道其名称的表中显示图像?
I explain better;我解释得更好; I have a table with three fields, id, title and image.我有一个包含三个字段的表,id、title 和 image。 In the image I am shown the name.在图像中,我显示了名称。 but I need the image to be shown.但我需要显示图像。
How can I fix this?我怎样才能解决这个问题?
let table = document.getElementById("my-table"); var xmlhttp = new XMLHttpRequest(); var url = "https://r2f5k3e89j.execute-api.us-east-2.amazonaws.com/articles"; xmlhttp.onreadystatechange = function () { var innerXmlhttp; if (this.readyState == 4 && this.status == 200) { var allart = JSON.parse(this.responseText); console.log(allart); allart.Items.forEach(item => { let child = document.createElement("tr"); child.innerHTML = ` <td>${item.id}</td> <td>${item.title}</td> <td>${item.image}</td>`; table.appendChild(child); }) } }; xmlhttp.open("GET", url, true); xmlhttp.send();
<table id="my-table" width="90%"> <tr> <th>Id</th> <th>Title</th> <th>Image</th> </tr> </table>
You should use image tag to do so您应该使用图像标签来这样做
let table = document.getElementById("my-table");
var xmlhttp = new XMLHttpRequest();
var url = "https://r2f5k3e89j.execute-api.us-east-2.amazonaws.com/articles";
xmlhttp.onreadystatechange = function () {
var innerXmlhttp;
if (this.readyState == 4 && this.status == 200) {
var allart = JSON.parse(this.responseText);
console.log(allart);
allart.Items.forEach(item => {
let child = document.createElement("tr");
child.innerHTML = `
<td>${item.id}</td>
<td><a href="http://google.com">${item.title}</a></td>
<td><img src='${item.image}' alt='Something' /></td>`;
table.appendChild(child);
})
}
};
xmlhttp.open("GET", url, true);
xmlhttp.send();
You can show image by using its source url.您可以使用其源 url 显示图像。 For example, if your image url which is coming from response json is https://example.com/image/url
then you can show it by using this url like that: For example, if your image url which is coming from response json is https://example.com/image/url
then you can show it by using this url like that:
<img src="https://example.com/image/url"/></td>`;
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