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如何在没有 Express 的情况下响应 Nodejs 中的动态内容

[英]How to response dynamic content in Nodejs without Express

      let reqBody = "";
      req
        .on("data", (chunk) => {
          reqBody += chunk.toString();
        })
        .on("end", () => {
        const body = new URLSearchParams(reqBody);
        res.end("ok");
        });

I'm trying to access the request's body using NodeJS without Express but for some reason, I could not run res.end("ok");我正在尝试使用没有 Express 的 NodeJS 访问请求的正文,但由于某种原因,我无法运行res.end("ok"); . .

You need to call req.end() as well您还需要调用req.end()

check Node.js document https://nodejs.org/api/http.html检查 Node.js 文档https://nodejs.org/api/http.html

With http.request() one must always call req.end() to signify the end of the request - even if there is no data being written to the request body使用 http.request() 必须始终调用 req.end() 来表示请求的结束 - 即使没有数据写入请求正文

 let reqBody = "";
  req
    .on("data", (chunk) => {
      reqBody += chunk.toString();
    })
    .on("end", () => {
    const body = new URLSearchParams(reqBody);
    res.end("ok");
    });
   req.end();

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