如何将列中的每一行更新为每个数组值，而不是将每一行更新为最后一个数组值？

Question

How do I update each row in the column to each array value, instead of each row updating to the last array value?

        foreach ($array as $i => $value) {
            $sql = "UPDATE table SET column_1='$value' WHERE column_2='value2'";
            mysqli_query($connDB, $sql);
        }

Input:

123
456
789

$array:

[0] => 123
[1] => 456
[2] => 789

Current result:

column_1	column_2
789	value2
789	value2
789	value2

What I want:

column_1	column_2
123	value2
456	value2
789	value2

Answer 1

You set $value1 in the query, change it to $value:

$sql = "UPDATE table SET column_1='$value' WHERE column_2='value2'";

         

Answer 2

the problem is column_2 is not unique for each row. you must have unique value like id in a table for proper updating or deleting so you can select id of all rows with condition column_2=value2 and then update each row using its unique id

Answer 3

My solution was to create a third column to determine the status of the whole row. Then, during each loop, the status would update with a limit of 1 row at a time. Only rows with 'updating' status can be changed. ('locked' is the status column default)

foreach ($array as $i => $value) {
        $status_update = "UPDATE table SET status='updating' WHERE column_2='value_2' AND status='locked' LIMIT 1";
        mysqli_query($connDB,$status_update);
        $value_update = "UPDATE table SET column_1='$value' WHERE status='updating'";
        mysqli_query($connDB, $value_update);
        $status_ready = "UPDATE table SET status='ready' WHERE column_2='value_2' AND status='updating'";
        mysqli_query($connDB, $status_ready);
    }

Results:

column_1	column_2	status
123	value_2	ready
456	value_2	ready
789	value_2	ready