获取 Java 中 windows 位置的规范化路径

Question

I have a requirement where I have a path as C:\..\bar for this the file bar gets created in the C drive when I use this path in SQL server. Now on using Apache's FilenameUtils, The normalize method returns null as also documented.

• C:\..\bar --> null

But I want

C:\bar for C:\..\bar

Is there any way in Java to get C:\bar for C:\..\bar I know that .. would mean parent directory but SQL server still creates file the C drive.

Answer 1

You can use getCanonicalFile .

import java.io.File;
import java.io.IOException;

public class Main {
    public static void main(String[] args) throws IOException {
        File file = new File("C:\\..\\bar");
        System.out.println(file.getCanonicalFile());
    }
}