XSD，使用无序元素创建模式，其中还包含列表
[英]XSD, create schema with unordered elements that also contains list
问题描述
I have that kind of XML:
我有那种XML：
<HEAD>
<BUYER>1111</BUYER>
<RECIPIENT>2222</RECIPIENT>
<ADDRESS>33333</ADDRESS>
<POSITION>
<NUMBER>1</NUMBER>
<NAME>Name 1</NAME>
</POSITION>
<POSITION>
<NUMBER>2</NUMBER>
<NAME>Name 2</NAME>
</POSITION>
<POSITION>
<NUMBER>3</NUMBER>
<NAME>Name 3</NAME>
</POSITION>
</HEAD>
BUYER , RECIPIENT , ADDRESS tags can be placed in any order, but before position tags . BUYER , RECIPIENT , ADDRESS标签可以按任何顺序放置，但在 position 标签之前。 Tags inside POSITION can be in any order. POSITION中的标签可以按任意顺序排列。
I was trying to use all tag to describe like this:我试图使用all标签来描述这样的：
<xs:element name="HEAD">
<xs:complexType>
<xs:all>
<xs:element name="BUYER">
<xs:element name="RECIPIENT">
<xs:element name="ADDRESS">
<xs:element name="POSITION" maxOccurs="unbounded" minOccurs="1">
<xs:complexType>
<xs:all>
<xs:element name="NUMBER">
<xs:element name="NAME">
</xs:all>
<xs:complexType>
</xs:element>
</xs:all>
</xs:complexType>
</xs:element>
Howerver, I found out that unbounded could not be used in all .但是，我发现unbounded all无法使用。
Is it possible to somehow make schema, that has unordered tags with array?是否有可能以某种方式制作具有数组无序标签的模式？
1 个解决方案
解决方案1
1 2022-02-02 11:57:23
In XSD 1.0 the only way to achieve this is to enumerate all permitted orderings of BUYER, RECIPIENT, and ADDRESS.在 XSD 1.0 中，实现此目的的唯一方法是枚举所有允许的 BUYER、RECIPIENT 和 ADDRESS 顺序。
In XSD 1.1 you could use xs:all to allow the elements to appear in any order, and then use an assertion to constrain it: test="every $P in POSITION satisfies empty($P/following-sibling::*[not(self::POSITION)]) .在 XSD 1.1 中，您可以使用 xs:all 来允许元素以任何顺序出现，然后使用断言对其进行约束： test="every $P in POSITION satisfies empty($P/following-sibling::*[not(self::POSITION)]) 。
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