正则表达式：查找以 # 符号开头的单词

Question

Could someone help to write regex in order to get the list of matched words like below? Words that start with the '#' symbol are references, so I need to grab them through the expression and do further work with them. References could only be alphanumeric and always starts with the '#' symbol. References can be preceded and/or followed by space, + - / * & ^ symbols.

Examples:

• '=#CELL1+2-#TABLE3' => Result of exec method: ["#CELL1", "#TABLE3"]
• '= 1 + #MyInput & #BillingAmount' => Result of exec method: ["#MyInput", "#BillingAmount"]
• '#input1=TODAY()*3 + #daily' => Result of exec method: ["#input1", "#daily"]

Answer 1

Please don't use a loop when there is String.match, you can use regex with global flag to find each case, below I made a solution by joining all inputs in a string but you can use it in separate strings.

 const input = ` =#CELL1+2-#TABLE3 = 1 + #MyInput & #BillingAmount #input1=TODAY()*3 + #daily `; console.log( input.match(/#\w+/g) );

Answer 2

const regex = /(\#\w+)/gm;
const str = `'#input1=TODAY()*3 + #daily'`;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}