通过子jq获取父元素的值

Question

Code:

{ 
"endpointAgents":[ 
{
      "agentId": "MyId",
      "agentName": "MYNAME",
      "location": {
        "locationName": "location"
      },
      "clients": [
        {
          "userProfile": {
            "userName": "Name"
          },
          "browserExtensions": [
            {
              "active": false
            }
          ]
        },
      ],
      "totalMemory": "16222 MB",
      "agentType": "enterprise"
    }

I need to return the agentId value with the value userName . I know how to do it with JSONPath

($.endpointAgents[?(@.clients.userName=~ 'a')].agentId)

, but don't know how with jq.

Answer 1

Assuming your input JSON is

{
  "endpointAgents": [
    {
      "agentId": "MyId",
      "agentName": "MYNAME",
      "location": {
        "locationName": "location"
      },
      "clients": [
        {
          "userProfile": {
            "userName": "Name"
          },
          "browserExtensions": [
            {
              "active": false
            }
          ]
        }
      ],
      "totalMemory": "16222 MB",
      "agentType": "enterprise"
    }
  ]
}

To get the agentId values from all items of the endpointAgents array where in the same object at least one object in the clients array has a userProfile.userName string value that contains a given substring, I'd go with

jq -r '
  .endpointAgents[]
  | select(.clients | map(.userProfile.userName | contains("a")) | any)
  | .agentId
'

MyId

Demo

In order import the query string from outside jq, use the --arg parameter

jq -r --arg query "a" ' … contains($query) … '