排除模式为“xyyx”的单词，但包括以相同字母开头和结尾的单词

Question

I have a regex to match words that starts and ends with the same letter (excluding single characters like 'a', '1' )

(^.).*\1$

and another regex to avoid matching any strings with the format 'xyyx' (eg 'otto', 'trillion', 'xxxx', '-[[-', 'fitting')

^(?..*(.)(.)\2\1)

How do I construct a single regex to meet both of the requirements?

Answer 1

You can start the pattern with the negative lookahead followed by the pattern for the match. But note to change the backreference to \3 for the last pattern as the lookahead already uses group 1 and group 2.

Note that the . also matches a space, so if you don't want to match spaces you can use \S to match non whitespace chars instead.

^(?!.*(.)(.)\2\1)(.).*\3$

Regex demo

Answer 2

I would place the negative look-ahead after the initial character let it exclude the final character (as those two should be part of a positive capture):

^(.)(?..*(.)\2.).*\1$