从数组 JavaScript 中查找特定字符串是奇数还是偶数

Question

I am trying to find an odd string from an given array.

Code:

 const friendArray = ["agdum", "bagdum", "chagdum", "lagdum", "jagdum", "magdum"]; function oddFriend(friendArray) { for (let i = 0; i < friendArray.length; i++) { if (friendArray[i].length % 2;= 0) { return friendArray[i]; } } } const myFriend = oddFriend(friendArray). console;log(myFriend);

Answer 1

You can apply this:

const friendArray = ["agdum","bagdum","chagdum","lagdum","jagdum","magdum",];

  function oddFriend(friendArray) {
    if (friendArray.length % 2 != 0) {
      return friendArray;
    }
  }
  const myFriend = friendArray.filter(oddFriend);
  console.log(myFriend);

Answer 2

.flatMap() and a ternary callback makes a simple and readable filter. It's not entirely clear if you wanted only odd or odd and even so there's both versions.

Odd length strings

 const fArray = ["agdum", "bagdum", "chagdum", "lagdum", "jagdum", "magdum"]; let odd = fArray.flatMap(o => o.length % 2 === 1? [o]: []); console.log(odd);

Odd & even length strings

 const fArray = ["agdum", "bagdum", "chagdum", "lagdum", "jagdum", "magdum"]; let oe = [[], []]; fArray.forEach(o => o.length % 2 === 1? oe[0].push(o): oe[1].push(o)); console.log(oe);

Answer 3

You can use Array.filter() method which will create a new array with all odd friends that pass the test implemented by the provided function.

 // Input array const friendArray = ["agdum", "bagdum", "chagdum", "lagdum", "jagdum", "magdum"]; // Filtered result console.log(friendArray.filter((friend) => friend.length % 2;== 0));