类方法的部分特化

Question

I'm trying to specialize a method of a (non-templated!) class. Apparently, it's not possible, however I am struggling to figure out why, or how to overcome the problem.

class MyClass {

public:
        template <typename... T>
        auto MyMethod(T... t) -> void { std::cout << "Original" << std::endl; }

        template <typename... T>
        auto MyMethod<int, T...>(int value, T... t) -> void { std::cout << "Specialization" << value << std::endl; }

};

int main(void) {
        MyClass myClass;
        myClass.MyMethod<char, char>('c', 'c');
        myClass.MyMethod<int, char>(123, 'c');

        return 0;
}

Answer 1

Only classes can be partially<\/em> specialized; methods can only be fully<\/em> specialized. As your methods still have template arguments ( T<\/code> ) that are not specified, this means a partial method specialization.