我不知道为什么它给我这个错误与 fastify-ts、multer 和 cloudinary

Question

I'm new to this, and I don't understand some things, but according to me this error is very strange, I'm using fastify-ts, multer and cloudinary, I want to tell result that the file path is the file to upload, but it doesn't tell me let

This is the code where I do the request:

 fastify.post<{ Body: CreatePublicationBody; Params: CreatePublicationParams; }>( "/create/:userId", { preHandler: upload, }, async (request, reply) => { const { description } = request?.body; const { userId } = request.params; const { path } = request.file; const result = await v2.uploader.upload(path); console.log(result); const payload = { userId: userId, description: description, image: result.secure_url, }; await fastify.store.Publication.create(payload, (err, data) => { if (err || !data) { throw new Error("Error to create Publication"); } else { return reply.status(200).send(data); } }); return "ok"; } );

This is the error it gives me

enter image description here

And this is how I record it:

 import fp from "fastify-plugin"; import multer from "fastify-multer"; import { File, FilesObject } from "fastify-multer/lib/interfaces"; import { v2 } from "cloudinary"; export default fp(async (fastify, opts) => { fastify.decorate("someSupport", function () { return "hugs"; }); void fastify.register(multer.contentParser); v2.config({ cloud_name: process.env.CLOUD_NAME, api_key: process.env.API_KEY, api_secret: process.env.API_SECRET, }); });

Answer 1

I believe your upload<\/code> method expects a callback function as the second parameter, like this:

cloudinary.uploader.upload(path, function(error, result) {console.log(result, error)});