"<i>why i cant return 2 value in a user defined function and display it in the main functionn?<\/i>为什么我不能在用户定义的函数中返回 2 个值并将其显示在主函数中？<\/b> <i>can someone help me<\/i>有人能帮我吗<\/b>"

Question

this countGender function need to receive what gender and return 2 value which is female or male

    int countGender(string gender)
    {
        int numGender[2] = {0};
        
        if(gender == "F")
        numGender[1]++;
        else if(gender == "M")
        numGender[2]++;
        
        return numGender[2];
    }

Answer 1

You're mismatching effect of function and object you want to store results. THe countGender<\/code> function looks like a mess resulting of shotgun debugging.

void countGender(int (&numGender)[2], string gender)
{    
    if(gender == "F") 
        numGender[0]++; 
    else if(gender == "M") 
        numGender[1]++; 
}

int main()
{
    string gender;
    int numGender[2] = {};
    int n;
    
    cout<<"Enter number of respondents:";
    cin>>n;
    
    for(int i=0; i<n; i++)
    {
        cout<<"\nEnter Gender (F-Female, M-Male):";
        cin>>gender;
        countGender(numGender,gender);
    }
    cout<<"\nFemale - "<<numGender[0];
    cout<<"\nMale - "<<numGender[1];
    return 0;
}