"在枚举中调用异步函数"

Question

I want to refactor my code from sync to async.我想将我的代码从同步重构为异步。 I use python and FastApi.我使用 python 和 FastApi。 I use the method which calls async function in Enumaration.我使用枚举中调用异步函数的方法。

for example:例如：

from enum import Enum

from app.story import get_story

    StoriesEnum = Enum(
        "StoriesEnum", {story: story  for story in get_story.story_list},
    )

Answer 1

As per the documentation<\/a> :根据文档<\/a>：

You might have noticed that await<\/code> can only be used inside of functions defined with async def<\/code> .您可能已经注意到await<\/code>只能在使用async def<\/code>定义的函数内部使用。

But at the same time, functions defined with async def<\/code> have to be "awaited".但同时，必须“等待”用async def<\/code>定义的函数。 So, functions with async def<\/code> can only be called inside of<\/strong> functions defined with<\/strong> async def<\/code> too.因此，具有async def<\/code>的函数也只能在<\/strong>使用async def<\/code>定义的函数<\/strong>内部调用。
<\/blockquote>

Thus, what you could do is:因此，您可以做的是：
 import asyncio async def go(): s = await get_story() s_list = s.story_list # ... asyncio.run(go())<\/code><\/pre> PS It would really help though, if you provided a minimal reproducible example<\/a> . PS 如果您提供了一个最小的可重现示例<\/a>，它确实会有所帮助。
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"在枚举中调用异步函数"

问题描述

1 个解决方案

解决方案1
0 2022-02-06 13:12:08

"在枚举中调用异步函数"

问题描述

1 个解决方案

解决方案1 0 2022-02-06 13:12:08

解决方案1
0 2022-02-06 13:12:08