"初始化类的静态数据成员时出错"

Question

class A{
    private:
        int x;
        static A a;
        static int  i;
    public:
        A(int y){
            std::cout<<y<<std::endl;
        }
};
int x = 10;
A a(x);
int A::i = x;

Answer 1

This is a peculiar language quirk - the scope resolution on the left, in int A::i<\/code> , affects the lookup scope on the right, so that actually refers to the x<\/code> member of A<\/code> .

int A::i = ::x;