如何在 php 中将动态 URL 传递给 curl - 出现错误 1

Question

I'm trying to pass a $url to curl using a function. the URL is built with a variable in it in the following method:

a.php // main page, include (a.php, b.php)
b.php // dynamic string function
c.php // curl function

I build a dynamic string successfully using sessions data // $_SESSION["input"] myDynamicstringfunction set a string by multiple sessions input values.

$dval = myDynamicstringfunction();
echo $dval;
// render correctly to: "-e5 -g6 -g7"

the $dval value is a string that resolve as expected. the $url is:

$url = "https://someurl.com/a/b?dc=-cv1.5 -a1 -b2 -c3 -d4 $dval";

The $url is render correctly with the

echo $url;
$url = "https://someurl.com/a/b?dc=-cv1.5 -a1 -b2 -c3 -d4 -e5 -g6 -g7";

I pass the $url to the curl function using:

$r = mycUrlfunction($url);

The curl function I use:

function singleRequest($url){
$ch = curl_init();
// set URL and other appropriate options
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HTTPGET, 1);
curl_setopt($ch, CURLOPT_HEADER, 0);

// grab URL and pass it to the browser
$curly = curl_exec($ch);
if ($curly == FALSE){
    die("cURL Error: " . curl_error($ch));
}

$result = json_decode($curly, true);

// close cURL resource, and free up system resources
curl_close($ch);

echo '<pre>';
return ($result);
}

The above get me an error (curl 1) - CURLE_UNSUPPORTED_PROTOCOL (1)

I have tried many things to get the $url to work with no success. if I set the $url value manually without the $dval variable like this:

$url = "https://someurl.com/a/b?dc=-cv1.5 -a1 -b2 -c3 -d4 -e5 -g6 -g7";

The code works just fine and I get the correct results from the API call. I tried using different quotes, {}, [], encoding to ASCII, vprintf(), and other solutions with no success.

Answer 1

the problem was with constructing the dynamic variable $dynamicstring of the URL initially used

$dynamicstring= "-a" . $_SESSION["a"]." -b".$_SESSION['b']." -c".$_SESSION['c']." -d".$_SESSION['d']."<br>";

this have a few problems

1. when using echo it render the expected output correctly
2. it have a "<br>" at the end
3. it have the wrong structure

the correct way to construct the $dynamicstring is to use {}

$dynamicstring= "-a{$_SESSION["a"]} -b{$_SESSION['b']} -c{$_SESSION['c']} -d{$_SESSION['d']}";