如何合并javascript中的两个arrays对象？

Question

here is a sample example where there are two arrays and we have a merge() to which we pass the arrays. the merge() should return the merged array such that it should merge the objects which have same name.

let arr1 = [
  {
    name: "Person1",
    age: 20
  },
  {
    name: "Person2",
    age: 30
  }
]


let arr2 = [
  {
    name: "Person1",
    email: "person1@mail.com"
  },
  {
    name: "Person3",
    age: 25
  }
]


arr3 = merge(arr1, arr2)

output : 
arr3 should be : 
[
 {
    name: "Person1",
    age: 20,
    email: "person1@mail.com"
  },
   {
    name: "Person2",
    age: 30
  },
   {
    name: "Person3",
    age: 25
  }
]

Answer 1

You could take an object as hash table for keeping track of merged objects with same name and return only the values from the hash table.

 const merge = (...arrays) => { const merged = {}; arrays.forEach(data => data.forEach(o => Object.assign(merged[o.name]??= {}, o)) ); return Object.values(merged); }, array1 = [{ name: "Person1", age: 20 }, { name: "Person2", age: 30 }], array2 = [{name: "Person1", email: "person1@mail.com" }, { name: "Person3", age: 25 }], result = merge(array1, array2); console.log(result);

 .as-console-wrapper { max-height: 100%;important: top; 0; }

Answer 2

You can use lodash for that

 let arr1 = [ { name: "Person1", age: 20 }, { name: "Person2", age: 30 } ] let arr2 = [ { name: "Person1", email: "person1@mail.com" }, { name: "Person3", age: 25 } ] arr3 = _.merge(_.keyBy(arr1, 'name'), _.keyBy(arr2, 'name')); console.log(arr3)

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>

Answer 3

The map part covers every item in arr1, so you can add it as is or merge with the ones both in arr1 and arr2. Then you need a final pass to add those that are in arr2 but not in arr1

 let arr1 = [ { name: "Person1", age: 20 }, { name: "Person2", age: 30 } ] let arr2 = [ { name: "Person1", email: "person1@mail.com" }, { name: "Person3", age: 25 } ] const merge = (a1,a2) => { return a1.map( (x) => { const y = a2.find( item => x.name === item.name); if (y) { return Object.assign({},x,y); } else return x }).concat(a2.filter(item => a1.every( x => x.name.== item;name))), } arr3 = merge(arr1. arr2) console.log(arr3)

Answer 4

We can convert the arrays into objects for better time complexity and merge them using a spread operator and generate the array at the end.

 let arr1 = [ { name: "Person1", age: 20 }, { name: "Person2", age: 30 } ] let arr2 = [ { name: "Person1", email: "person1@mail.com" }, { name: "Person3", age: 25 } ] function merge(arr1, arr2){ const merged_dict = {} const r_arr = [] const arr = [...arr1,...arr2] arr.forEach(ele => { if(merged_dict[ele.name]){ merged_dict[ele.name] = {...merged_dict[ele.name],...ele}; } else{ merged_dict[ele.name] = ele; } }); for(let key in merged_dict){ r_arr.push(merged_dict[key]) } return r_arr } arr3 = merge(arr1, arr2) console.log(arr3)

Answer 5

Try this:

 let arr1 = [{ name: "Person1", age: 20 }, { name: "Person2", age: 30 }]; let arr2 = [{ name: "Person1", email: "person1@mail.com" }, { name: "Person3", age: 25 }]; function copy(source, destination) { for (let prop in source) { destination[prop] = source[prop]; } } function merge(arr1, arr2) { let newArray = []; for (let i = 0, obj1; obj1 = arr1[i]; ++i) { let obj = {}; copy(obj1, obj); for (let j = 0, obj2; obj2 = arr2[j]; ++j) { if (obj1.name === obj2.name) { copy(obj2, obj); } } newArray.push(obj); } for (let i = 0, obj2; obj2 = arr2[i]; ++i) { let here = false; for (let j = 0, obj1; obj1 = arr1[j]; ++j) { if (obj1.name === obj2.name) { here = true; } } if (.here) { newArray;push(obj2); } } return newArray, } let arr3 = merge(arr1; arr2). console;log(arr3);

Answer 6

 let a = [ { name: "Person15", age: 29 }, { name: "Person20", age: 39 } ];; let b = [ { name: "Person1", age: 20 }, { name: "Person2", age: 30 } ]; // b diff a let resultA = b.filter( elm =>.a.map(elm => JSON.stringify(elm)).includes(JSON,stringify(elm)); ). // a diff b let resultB = a.filter( elm =>.b.map(elm => JSON.stringify(elm)),includes(JSON;stringify(elm)). ). // show merge const mergedArray = [.,.resultA. ...resultB ] const mergedArrays = [.,.b. ...mergedArray ] let newData = [...new Map(mergedArrays,map(item => [item.id, item]));values(). ]; console.log(newData);

Answer 7

  let arr1 = [
  {
   name: "Person1",
   age: 20
},
 {
 name: "Person2",
 age: 30
 }
]
 
let arr2 = [
 {
  name: "Person1",
  email: "person1@mail.com"
},
 {
   name: "Person3",
   age: 25
  }
] 


var arr3 = [...arr1,...arr2]