[英]How can I convert a fraction expression into a character vector in R?
Hello an thanks for the help.您好,感谢您的帮助。
I want to convert the expression: x / y (eg 1298 / 1109) into a character vector: "x / y" (eg "1298 / 1109") using R.我想使用 R 将表达式:x / y(例如 1298 / 1109)转换为字符向量:“x / y”(例如“1298 / 1109”)。
I have tried it with as.character(x/y) and with as.character.Date(x/y) but this only turns the result of the fraction into a character vector.我已经尝试使用 as.character(x/y) 和 as.character.Date(x/y) 但这只会将分数的结果转换为字符向量。
Do you mean this?你是这个意思吗?
> deparse(quote(1298 / 1109))
[1] "1298/1109"
or或者
> f <- function(x) deparse(substitute(x))
> f(1298 / 1109)
[1] "1298/1109"
An alternative solution using paste
, as mentioned by Allan in the comments, wrapped in a function. Not as flexible as the solution by Tomas, but simple.使用
paste
的替代解决方案,正如 Allan 在评论中提到的,包装在 function 中。不如 Tomas 的解决方案灵活,但简单。
f <- function(x,y) {
paste(x, y, sep = " / ")
}
f(1298, 1109)
[1] "1298 / 1109"
As an addition to the excellent answers already given, in case that one wants to be able to evaluate the expression at some point you can take this approach.作为已经给出的优秀答案的补充,如果有人希望能够在某个时候评估表达式,您可以采用这种方法。
x <- 1298
y <- 1109
z <- as.expression(substitute(x / y, list(x = x, y = y)))
z
# expression(1298/1109)
class(z)
# [1] "expression"
eval(z)
# [1] 1.1704
as.character(z)
# [1] "1298/1109"
Or without making it an expression
或者不让它成为一个
expression
t <- substitute(x / y, list(x = x, y = y))
t
# 1298/1109 # not a string, but a "call"
class(t)
# [1] "call"
eval(t)
# [1] 1.1704
deparse(t)
# [1] "1298/1109"
With MASS
, there is fractions
function对于
MASS
,有fractions
function
MASS::fractions(1298/1109)
[1] 1298/1109
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