无法从 PHP 中的另一个文件获取 object 属性

Question

I want to make a query to MySQL and if the query is done but if there is no result, I want to set "login_status" object property to false instead of NULL.

I have all files connected in one main file "load.php" so there is no problems with including files.

My query is defined in User.php file which containes User class with method login().

Another file is login.view.php which is html template for login functionality, but I receive message that variable $user (isntance of User) is not defined and that property login_status isn't also defined.

Here's the code from User.php:

class User extends Query {
    public $login_status;
    
    public function login(){
        $email = $_POST['login_email'];
        $pass = $_POST['login_pass'];
    
        $sql = "SELECT * 
                FROM tqyr_users 
                WHERE user_email = ? 
                AND user_pass = ?;";
        $query = $this->db->prepare($sql);
        $query->execute([$email, $pass]);
        $is_user = $query->fetch(PDO::FETCH_OBJ);
    
        if(is_object($is_user)){
            $_SESSION['logged'] = $is_user;
            header('Location: index.php');
        } else {
            $this->login_status = false;
            header('Location: login.php');
        }
    }.........

And here's the code from login.view.php:

    <?php if($user->login_status == false): ?>
    <p class="px-4 py-4 bg-danger text-white text-start mb-4 login-alert">Wrong email or password, please try again.</p>
 

     <?php endif; ?>

Once again, I have all files connected and I have defined $user instance

Answer 1

If 'else' is executed, it will force a new connection and consequently you will lose the variable state.

I suggest you change the responsibility of $_SESSION and header of this class.

You can return true or false in login function.