如何格式化/重塑我的数据以获得每个 object 的单独数据？

Question

Currently, my data is in a nested list as [[ID1, Pos1, Time1], [ID2, Pos2, Time2], [ID1, Pos3, Time3]....].

I then put that into a Pandas dataframe. I want to graph position (Pos values) against time for each object ID separately in Plotly, and my searches of plotly documentation haven't helped. What I'd like is for each object ID to have a separate Pos vs Time line plot on the same figure.

How would I do this? I'm unsure whether I should reshape my data first so that repeated ID values are grouped somehow or whether I can do this direct from the plotly plotting function. I'm new at this, so any help would be greatly appreciated.

Here's the code snippet:

dataset=[]
for obj in scene.objects:
    obj_data = [obj.ID, obj.time, obj.pos]
    dataset.append(obj_data)

df = pd.DataFrame(data=dataset, columns=["ID", "Time", "Pos"])
 

Also, the output of the first five entries of the dataframe:

    ID  Time  ...  Speed  
0   4   0.0  ...   1.465062   
1   5   0.0  ...   1.195697 
2   6   0.0  ...   1.443732  
3   7   0.0  ...   1.318886   
4   8   0.0  ...   1.258748  

Answer 1

You could group the data in your dataframe by "ID" and then add a line plot to the same figure:

import plotly.graph_objs as go


fig = go.Figure()  # Same figure object

for group_name, group_df in df.groupby(["ID"]):
    # group_name is the "ID" value
    # group_df is a dataframe with the rows of each "ID" value
    fig.add_trace(
        go.Scatter(  # This is how we draw a line plot
            x=group_df["Time"], y=group_df["Pos"],
            name=group_name,  # Add the "ID" as the name of the line
        )
    )

fig.show()  # Display figure

This is a sample input and expected output using this code:

   ID  Pos  Time
0   1    1     1
1   1    3     2
2   0    2     1
3   0    4     2