如何根据两列日期和时间在 pandas 中创建日期时间列？

Question

Lets say I have following DataFrame :

import pandas as pd
df = pd.DataFrame({"Date":["2022-01-01", "2022-01-02", "2022-01-03"], "Time":[0,1,10]})

I want another column which is a datetime using the Date and the Time Columns.

Expected result

         Date  Time            DateTime
0  2022-01-01     0 2022-01-01 00:00:00
1  2022-01-02     1 2022-01-02 01:00:00
2  2022-01-03    10 2022-01-03 10:00:00

Trial

I tried this failed solution:

df["DateTime"] = str(df["Date"]) + " " + str(df["Time"]) + ":00"

Which outputs:

>>> df
         Date  Time                                           DateTime
0  2022-01-01     0  0    2022-01-01\n1    2022-01-02\n2    2022-01...
1  2022-01-02     1  0    2022-01-01\n1    2022-01-02\n2    2022-01...
2  2022-01-03    10  0    2022-01-01\n1    2022-01-02\n2    2022-01...

Answer 1

You can just do Date and Time add with to_datetime and to_timedelta

df['new'] = pd.to_datetime(df['Date']) + pd.to_timedelta(df['Time'],unit='hour')
df
Out[388]: 
         Date  Time                 new
0  2022-01-01     0 2022-01-01 00:00:00
1  2022-01-02     1 2022-01-02 01:00:00
2  2022-01-03    10 2022-01-03 10:00:00

Answer 2

One solution would be the following:

df["DateTime"] = df["Date"].astype(str) + " " + df["Time"].astype(str) + ":00"

Then convert to datetime :

df["DateTime"] = pd.to_datetime(df["DateTime"])

Hence the output is as expected:

>>> df
         Date  Time            DateTime
0  2022-01-01     0 2022-01-01 00:00:00
1  2022-01-02     1 2022-01-02 01:00:00
2  2022-01-03    10 2022-01-03 10:00:00

Answer 3

df['date'] = [d.date() for d in df['datetime']]
df['time'] = [d.time() for d in df['datetime']]
df['date']= pd.to_datetime(df['date'])